Question

(a + b + c)2 – (a + b + c)?​

Answer 1

Answer:

Let (b + c) = x

Then (a + b + c)2 = (a + x)2 = a2 + 2ax + x2

= a2 + 2a (b + c) + (b + c)2

= a2 + 2ab + 2ac + (b2 + c2 + 2bc)

= a2 + b2 + c2 + 2ab + 2bc + 2ca

Therefore, (a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ca

Answer 2

a^2+b^2+c^2+ab+bc+ca-(a+b+c)

a^2+b^2+c^2+ab+ba+ca-a-b-c

hence proved

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