Question

(a+b+c)^2-(a-b-c)^2​

Answer 1

Answer:

Step-by-step explanation:

(a+b+c)^2 – (a-b-c)^2

This equation is of the form

x^2 – y^2= (x+y)(x-y)

(a+b+c)^2 – (a-b-c)^2

=(a+b+c+a-b-c){a+b+c-(a-b-c)}

=(2a)(a+b+c-a+b+c)

=(2a)(2b+2c)

=4ab + 4ac

Answer 2

Step-by-step explanation:

(a+b+c)² - (a-b-c)²

= (a²+b²+c²+2ab+2bc+2ca) - ( a²+b²+c²-2ab+2bc-2ca)

= a²+b²+c²+2ab+2bc+2ca - a² - b²-c² +2ab -2bc + 2ca

= 4ab + 4ca

= 4(ab+bc)

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