Question

(a + b + c)²– (a - b - c)²​

Answer 1

(a+b+c)^2=a^2 + b^2 + c^2 + 2ab + 2bc + 2ac

(a - b - c)² = a^2 +b^2 +c^2 -2ab+2bc-2ac

(a + b + c)²– (a - b - c)²=(a^2 + b^2 + c^2 + 2ab + 2bc + 2ac) - (a^2 +b^2 +c^2 -2ab+2bc-2ac)

=2ab+2ac+2ab+2ac

=4ab+4ac

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Answer 2

Answer:

The value is 4ab+4ca

Step-by-step explanation:

$[a+b+c]^{2}$-$[a-b-c]^2$

$[a^2+b^2+c^2+2ab+2bc+2ca]$ -- $[a^2-b^2-c^2-2ab+2bc-2ca]$

[2ab+2ab+2ca+2ca]

[4ab+4ca]