Math, asked by kamlasharma201p3j0rx, 1 year ago

(a+b+c)^2 + (a-b-c)^2

Answers

Answered by samky
2
this is the answer hope it helps
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Answered by abhi569
0
(a + b + c)² + (a - b-c )²

(a + b +c)^2 + [a + (-b) + (-c)]^2
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Using formula,
(a + b+c)^2 = a^2 + b^2 + c^2 + 2(ab + bc + ca)

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(a + b+ c)^2 + [a + (-b) + (-c)]^2

[a^2+b^2+c^2+2(ab+bc+ca)]+[a^2+(-b)^2+(-c)^2+2{(a*-b)+(-b*-c)+ ( -c *a) }

a^2+b^2+c^2+2ab+2bc+2ac+a^2+b^2+c^2-2ab+2bc-2ca

2a^2 + 2b^2 + 2c^2 + 4bc

2(a^2 + b^2 + c^2 + 2bc)

2[ (c+b)^2 + a^2]



i hope this will help you


-by ABHAY

abhi569: please go back and see it again
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