(a+b+c) 2+ (a-b+c)2 +(a+b-c)2
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(a+b+c) 2+ (a-b+c)2 +(a+b-c)2
solution
by rearranging
2(a+b+c) + 2(a-b+c) + 2(a+b-c)
by taking 2 as comman from 3 terms
2 [ (a+b+c) + (a-b+c) + (a+b-c)]
2 [ a+b+c + a-b +c+ a+b-c]
2[ 3a + b + c ]
6a + 2b + 2c
hope it helps
hope it helpsbe brainly
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