Math, asked by mdkaif6090, 11 months ago

(a+b+c)^2 + (a-b-c)^2 + (-a-b-c)^2
solve these:​

Answers

Answered by mkaif2196
1

Answer:

{{a}^{2}  +  {b}^{2}  +  {c }^{2}  + 2ab + 2bc + 2ca} +  {{a}^{2}  +  { - b}^{2}  +  { - c}^{2}  + 2a( - b) + 2( - b)( - c) + 2( - c)a} + { { - a}^{2}  +  { - b}^{2} +  { - c}^{2}  + 2( - a)( - b) + 2( - b)( - c) + 2( - c)( - a)} \\  {a}^{2}  +  {b}^{2}  +  {c}^{2}  + 2ab + 2bc + 2ca +  {a}^{2}  +  {b}^{2}  +  {c}^{2}   - 2ab + 2bc - 2ca +  {a}^{2}  +  {b}^{2}  +  {c}^{2}  + 2ab + 2bc + 2ca \\ 3 {a}^{2}  + 3 {b}^{2}  + 3 {c}^{2}  + 2ab + 6bc + 2ca

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