Question

(a+b+c)²+(a-b-c)²? please solve..​

Answer 1

Step-by-step explanation:

2(a²+b²+c²+2bc) is the answer..

Answer 2

Answer:

(a+b+c+c)+(a-b-c-c)

(1+2=2,3+3=9)+(2-1=1,3-3=0)

Step-by-step explanation:

$2 ^{2} +9 ^{2} + 1 ^{2} + 0 ^{2}$

$4 ^{2} + 18 ^{2} + 1 + 0$

$4 - 4 + 18 - 18 + 1 - 1 - 0 - 0$

$0 + 0 + 0 + 0 = 0 + 1 = 1$

answer is

$1$