Question

(a+b+c)2=a2+b2+c2+2ab+2bc+2ac prove this

Answer 1

Answer:

$(a + \: b + \: c) {}^{2} = (a + \: b + \: c) \times (a + \: b + \: c) \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:= {a}^{2} + ab + ac + ab + {b}^{2} + bc + ac + bc + {c}^{2} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = {a}^{2} + {b}^{2} + {c}^{2} + 2ab + 2bc + 2ac \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: or \: \: \: {a}^{2} + {b}^{2} + {c}^{2} + 2(ab + \: bc + \: ac)$

Answer 2

Answer:

hey mate here is answer