(a+b+c)² = a² + b² + c² + 3ab + 3bc +3ac
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Answer:
(a+b+c)²=a²+b²+c²+2ab+2bc+2ca
Step-by-step explanation:
(a+b+c) (a+b+c)
a(a+b+c)+b(a+b+c)+c(a+b+c)
a²+ab+ac+ab+b²+bc+ac+bc+c²
a²+ab+ab+ca+ca+bc+bc+b²+c²
a²+2ab+2ca+2bc+b²+c²
a²+b²+c²+2ab+2bc+2ca
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