Math, asked by yuvasreerani, 9 months ago

(a-b+c)²+(b-c+a)²+2(a-b+c)(b-c+a)

Answers

Answered by Josephrudyardroot

0

Answer:

(a-b+c)²+(b-c+a)²+2(a-b+c)(b-c+a)=(a-b+c+b-c+a)²=(2a)²=4a²

USING a²+b²+2ab=(a+b)²

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