(a-b-c)² explain the trinomial formula
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(a-b-c)²
=> [a +(-b) +(-c)] ²
=> a² +(-b)² +(-c)² +2[-ab+bc-ac]
=> a² + b²+c² -2ab + 2bc - 2ac
=> [a +(-b) +(-c)] ²
=> a² +(-b)² +(-c)² +2[-ab+bc-ac]
=> a² + b²+c² -2ab + 2bc - 2ac
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Heya ✋
Let see your answer !!!!
Thanks :)))))
Let see your answer !!!!
Thanks :)))))
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