Question

(a+b-c)² is equal to​

Answer 1

Answer:

Hello mate!

Using the identity $(x+y+z)^{2} = x^{2} +y^{2} +z^{2} +2xy+2zy+2zx$,

so , $x = a ; y= b; z= -c$,

$(a+b-c)^{2} = a^{2} + b^{2} + (-c)^{2} + 2*a*b + 2*b* -c + 2*a*-c$

                  =$a^{2} +b^{2} +c^{2} +2ab -2bc - 2ac$.