a+b+c=27✓29 find ✓asquare+bsquare+csquare
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√(a² + b² + c²) = 87 if 3a = 4b = 6c & a + b + c = 27√29
Step-by-step explanation:
Missing information :
3a = 4b = 6c
Let say 3a = 4b = 6c = 12k
=> a = 4k
b = 3k
c = 2k
a + b + c = 27√29
4k + 3k + 2k = 27√29
=> 9k = 27√29
=> k = 3√29
a = 4k = 12√29
b = 3k = 9√29
c = 2k = 6√29
√(a² + b² + c²)
= √ ( (12√29)² + (9√29)² + (6√29)²)
= √(29)( 144 + 81 + 36)
= √(29(261)
= √29 * 29 * 9
= 29 * 3
= 87
Learn more:
If 3a=4b=6c a+b+c=27√29 find - Brainly.in
https://brainly.in/question/1314952
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