a+b+c=2s show that b2+c2-a2+2bc=4s(s-a).
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b² + c² - a² + 2bc = 4s(s - a)
Step-by-step explanation:
a+b+c=2s show that b²+c²-a²+2bc = 4s(s-a).
a+b+c=2s
=> b + c = 2s - a
Squaring both sides
=> (b + c)² = (2s - a)²
=> b² + c² + 2bc = 4s² + a² - 4as
=> b² + c² + 2bc - a² = 4s² - 4as
=> b² + c² - a² + 2bc = 4s(s - a)
QED
Proved
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