Question

a+b+c=2s show that B2+c2-a2+2bc=4s(s-a)​

Answer 1

b? + c? - a? + 2bc = 4s(s - a)

Step-by-step explanation:

a+b+c=2s show that b?+c?-a?+2bc = 4s(s- = a).

a+b+c=2s

=> b + c = 2s - a

Squaring both sides

=> (b + c)² = (2s - a)?

=> b? + c? + 2bc = 4s? + a² - 4as =

=> b? + c? + 2bc - a? = 4s? - 4as =

=> b² + c2 - a? + 2bc = 4s(s - a)

QED

Proved