a+b+c=2s show that B2+c2-a2+2bc=4s(s-a)
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b? + c? - a? + 2bc = 4s(s - a)
Step-by-step explanation:
a+b+c=2s show that b?+c?-a?+2bc = 4s(s- = a).
a+b+c=2s
=> b + c = 2s - a
Squaring both sides
=> (b + c)² = (2s - a)?
=> b? + c? + 2bc = 4s? + a² - 4as =
=> b? + c? + 2bc - a? = 4s? - 4as =
=> b² + c2 - a? + 2bc = 4s(s - a)
QED
Proved
Step-by-step explanation:
a+b+c=2s show that b?+c?-a?+2bc = 4s(s- = a).
a+b+c=2s
=> b + c = 2s - a
Squaring both sides
=> (b + c)² = (2s - a)?
=> b? + c? + 2bc = 4s? + a² - 4as =
=> b? + c? + 2bc - a? = 4s? - 4as =
=> b² + c2 - a? + 2bc = 4s(s - a)
QED
Proved
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