A+B+C=3π/2 then find the value of cos2A+cos2B+cos2C
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A+B+C=3pie/2
multiply both sides with 2
2[A+B+C]=2[3pie/2]
apply cos on both sides
cos2[A+B+C]=cos6pie/2
cos2A+cos2B+cos2c=cos3pie
multiply both sides with 2
2[A+B+C]=2[3pie/2]
apply cos on both sides
cos2[A+B+C]=cos6pie/2
cos2A+cos2B+cos2c=cos3pie
Arjeeta:
but it is wrong
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