Question

a+b+c=3 a^2+b^2+c^2=6 1/a+1/b+1/c=1 find values of a , b and c No spam

Answer 1

Answer:

$\huge\underbrace\red{Answer⇒}$

$(a2+b2+c2). ⇒2(ab+bc+ca)=12−2=−1. ⇒ab+bc+ca=−12.$