Question

a+b+c=3
a²+b²+c²=6. and
1/a+1/b+1/c = 1
then abc is.....?
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Answer 1

1/a + 1/b + 1/c

= ab + bc + ca )/ abc = 1

ab + bc + ca = abc

( a+b+c) = 3

( a+ b+c)^2 = 9

a^2 + b^2 + c^2 + 2( ab+ bc+ ca) = 9

6 + 2abc = 9

2abc = 3

abc= 3/2

Answer 2

the answer is

1/a+1/b+1/c=1

a+b+c/abc =1

a+b+c = abc

a+b+c = 3 (given)

3 = abc

or

abc=3/2

Therefore please look at it and mark me as brainliest or follow me