Math, asked by tejaswitanu2001t, 1 year ago

(a+b+c)³ - a³ - b³ - c³ = 3(a+b)(b+c)(c+a) 

Answers

Answered by Anonymous
6
(a+b+c)^3=a^3+b^3+c^3+3(a+b)(b+c)(c+a)
(a+b+c)^3-a^3-b^3-c^3=a^3+b^3+c^3+3(a+b)(b+c)(c+a)-a^3-b^3-c^3
                                 ⇒3(a+b)(b+c)(c+a)
Answered by Anonymous
17
(a+b+c)³ = a³ + b³ + c³ + 3(a+b)(b+c)(c+a)
LHS = (a+b+c)³ - a³ - b³ - c³
= [a³ + b³ + c³ + 3(a+b)(b+c)(c+a)] - a³ - b³ - c³                           
= 3(a+b)(b+c)(c+a)
= RHS
Similar questions