Math, asked by vivekhruday, 1 year ago

(a+b+c)^3 try to answer

Answers

Answered by SwtTanya
1
a3+b3+c3=(a+b+c)3−[3a2(b+c)+3b2(c+a)+3c2(a+b)+6abc]a3+b3+c3=(a+b+c)3−[3a2(b+c)+3b2(c+a)+3c2(a+b)+6abc]
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