Question

(a+b+c)^3=?
What is the full equation?​

Answer 1

Answer:

[A+(B+C)]3=A3+(B+C)3+3[A∗(B+C)]∗(A+B+C)=A3+B3+C3+3BC(B+C)+3(AB+AC)(A+B+C)

⇒(A+B+C)3=A3+B3+C3+3B2C+3BC2+3(A2B+AB2+ABC+A2C+ABC+AC2)

⇒ (A+B+C)3=A3+B3+C3+3B2C+3BC2+3(A2B+AB2+2ABC+A2C+AC2)

⇒(A+B+C)3=A3+B3+C3+3B2C+3BC2+3A2B+3AB2+6ABC+3A2C+3AC2

⇒(A+B+C)3=A3+B3+C3+6ABC+3(A2B+AB2+B2C+BC2+A2C+AC2)

⇒(A+B+C)3=A3+B3+C3+6ABC+3[A2(B+C)+B2(C+A)+C2(A+B)]

⇒(A+B+C)3=A3+B3+C3+3(A+B)(B+C)(C+A)

It implies that,

(a+b+c)3= a3+b3+c3+3(a+b)(b+c)(c+a)

Step-by-step explanation:

Answer 2

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