a+b-c=3pi then sina+sinb-sinc is equal to
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Given : a + b - c = 3pi
To find : sina + sinb - sinc
Sol : a + b - c = 3pi
multiplying sin in both LHS and RHS, we get :
sin ( a + b - c) = sin ( 3pi)
sina + sinb - sinc = 3 * sin * pi = 3sinpi
Hope this helps you dear...
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To find : sina + sinb - sinc
Sol : a + b - c = 3pi
multiplying sin in both LHS and RHS, we get :
sin ( a + b - c) = sin ( 3pi)
sina + sinb - sinc = 3 * sin * pi = 3sinpi
Hope this helps you dear...
plz mark my answer brainliest if you find it useful...
if you find any queries in understanding this, then plz ask me here in the comments box!!!
^_^
vaibhavkallurkpbhts6:
I have a doubt.
We have some options as well.. A]4sina/2*sinb/2*sinc/2 [B]-4sina/2*sinb/2*sinc/2 [c] 4cosa/2*cosb/2*cosc/2 [D] -4cosa/2*cosb/2*cosc/2
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