a+b+c=3x,then find the value of(x-a)3+(x-b)3+(x-c)3
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0
Answer:
0
Step-by-step explanation:
(x - a)3 + (x - b)3 + (x - c)3
= 3x - 3a + 3x - 3b + 3x - 3c
Re-arranging the terms,
= 3x + 3x + 3x - 3a - 3b - 3c
= 9x - 3 (a + b + c)
But, a + b +c = 3x
= 9x - 3 (3x)
= 9x - 9x
= 0
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