a+b+c=5 and ab+bc+ca=10 then prove that a^3+b^3+c^3-3abc=-25
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a^3 + b^3 + c^3 - 3abc =
(a+b+c) (a^2 + b^2 + c^2 - (ab + bc + ac))
(5)*(15-10) = 5*5 = 25
(a+b+c) (a^2 + b^2 + c^2 - (ab + bc + ac))
(5)*(15-10) = 5*5 = 25
rohitkunvar:
(a+b+c) = a^2 + b^2 + c^2 + 2(ab+bc+ca)
5^2 = a^2 + b^2 + c^2 + 2*10
therefore a^2........ = 25-2*5 = 15
there are some mistakes plzz correct them
now plzz mark me as brainliest
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