Question

a+b+c=5
b^2+ac=25
ac-bc=28
a+bc=?​

Answer 1

Answer:

The ascending order of 16 7 12 , 81 3 8, 625 2 3 is _____. (A) 16 7 ... If log log log a b c 5 6 7 = = , then b2 = (A) ac (B) a2 (C) bc (D) ab 25. ... x x x 5 50++= (A) 1 (B) 9 (C ...

Answer 2

Given :

$a+b+c=5\hfill (1)$

$b^2+ac=25\hfill (2)$

$ac-bc=28\hfill (3)$

To find : the value of a+bc.

Step-by-step explanation:

From (1) we get, a=5-b-c substitite in (2) and (30 respectively we get,

$b^2+5c-bc-c^2=25\hfill (4)$

$5c-bc-c^2-bc=28\hfill (5)$

Substract (4) from (5) we get,

$b^2+bc=-3$

Now consider (3),

$bc=ac-28=25-b^2-28=-b^2-3$

$a+bc=a-b^2-3$