Math, asked by CapBlissSaigi1615, 2 months ago

a+b+c=6
a²+b²+c²=14
a³+b³+c³=36
abc=

Answers

Answered by anku3842
2

Answer:

a+b+c=6,a

2

+b

2

+c

2

=14,a

3

+b

3

+c

3

=36

(a+b+c)=a

2

+b

2

+c

2

+2(ab+bc+ca)

⟹2(ab+bc+ca)=(6)

2

−14

⟹2(ab+bc+ca)=(6)

2

−14

=36−14=22

ab+bc+ca=11

Now ,we know a

3

+b

3

+c

3

−3abc=(a+b+c)(a

2

+b

2

+c

2

−(ab+bc+ca))

⟹36−3abc=6(14−11)

⟹36−3abc=6×3=18

⟹3abc=18

⟹abc=6

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