Question

a+b+c=6&ab+ac+ca=11 find the value of.
a^3+b^3+c^3=3abc​

Answer 1

$\huge\blue{•Answer:}$

a³+b³+c³-3abc=(a + b + c)(a² + b² + c² - ab - bc - ca)

Now,

(a+b+c)²=a²+b²+c²+2(ab+bc+ca)

=36=a²+b²+c²+2(11)

=36-22=a²+b²+c²

=a²+b²+c²=14

put the values......

a³+b³+c³-3abc

=(a + b + c)(a² + b² + c² - ab - bc - ca)

=6 x {14-(ab+bc+ca)}

=6x (14-11)

=6x3

=18

Answer 2

Answer:

yrr Khushboo........ How was the exam of Science???????.....

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