Question

a+b+c=6 and a^2+b^2+c^2=14 then find the value of ab +bc+ca

Answer 1

Step-by-step explanation:

( a + b + c) = 6

a² + b² + c² = 14

ab + bc + ca = ?

Let's use (a + b + c )² Property

So a² + b² + c² = a² + b² + c² + 2ab + 2bc + 2ca

(a + b + c)² = 6²

=> (a² + b² + c²) + 2ab + 2bc + 2ac = 36

=> 14 + 2( ab + bc + ca) = 36

=> 2( ab + bc + ca) = 36 - 14

=> 2( ab + bc + ca) = 22

=> ab + bc + ca = 22/2

=> ab + bc + ca = 11

Therefore, ab + bc + ca = 11

Hope this helps.....

Answer 2

Answer:

your answer attached in the photo