Question

a+b+c = 6and ab+BC+CA= 11. find a³+b³+c³​

Answer 1

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Answer 2

$\huge \bold\red{Answer❀✿°᭄}$

-4 is the answer...

Solution:-

a+b+c=6 and ab+bc+ca=11

Let a =3

b=1 and

c=2

Now, putting the values in the given equations.

a+b+c=6 and ab+bc+ca=11

3+1+2=6 and 3*1+1*2+3*2=11

3+2+6=11. 11=11

Now, put the values in the equation we have to find that is

a^2+b^2+c^c-3abc

3^2+1^2+2^2–3*3*1*2

9+1+4–18

14–18

-4.

Hence, the answer is -4..