A+b+c=6Then value (2-a)3+(2-b)3+(2-c)3-(2-a) (2-b) (2-c)is
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a + b + c = 6
a + b + c = 2 + 2 + 2
0 = (2 - a) + (2 - b) + (2 - c)
(2 - a ) + (2 - b ) + (2 - c ) = 0
we know,
when , x + y + z = 0
then, x³ + y³ + z³ - 3xyz = 0
so,
(2 - a )³ + (2 - b)³ + (2 - c)³ -3(2 - a )(2 - b)(2 - c) = 0
a + b + c = 2 + 2 + 2
0 = (2 - a) + (2 - b) + (2 - c)
(2 - a ) + (2 - b ) + (2 - c ) = 0
we know,
when , x + y + z = 0
then, x³ + y³ + z³ - 3xyz = 0
so,
(2 - a )³ + (2 - b)³ + (2 - c)³ -3(2 - a )(2 - b)(2 - c) = 0
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