Question

A+b+c=7 abc=-72a^2b+b^2a+b^2c+c^2b+c^2a+a^2c=34a^3+b^3+c^3=?​

Answer 1

Answer:

${(a + b + c)}^{3} = {a}^{3} + {b}^{3} + {c}^{3} + 6abc + 3( {a}^{2} b \\ + {a}^{2} c + {b}^{2} a + {b}^{2} c + {c}^{2} b + {c}^{2} a) \\ on \: putting \: the \: given \: information \: in \: the \\ above \: equation \\ {7}^{3} = ({a}^{3} + {b}^{3} + {c}^{3} ) + 6 \times ( - 72) + 3 \times 34 \\ 343 = ({a}^{3} + {b}^{3} + {c}^{3} ) - 432 + 102 \\ ({a}^{3} + {b}^{3} + {c}^{3} ) = 343 + 432 - 102 \\ = 673$