Question

a+b+c=7 and ab+bc+ca=15. prove that a^3+b^3+c^3-3abc=28​

Answer 1

Answer:

a³+b³+c³=(a+b+c)(a²+b²+c²-ab-bc-ac)

a²+b²+c²=49-30=19

a³+b³+c³=28

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