Math, asked by divyanshbhati192004, 1 year ago

a+b+c =7and ab+bc+ca=12then
Find the value of a^3+b^3+c^3-3abc

Answers

Answered by Anonymous
1

Answer:

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Answered by Ashishkumar098
1

Answer :-

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a + b + c = 7

ab + bc + ca = 12

Now ,

( a + b + c )³ = a³ + b³ + c³ - 3abc + 2 ( ab + bc + ca )

( 7 )³ = a³ + b³ + c³ - 3abc + 2 × 12

343 = a³ + b³ + c³ - 3abc + 24

a³ + b³ + c³ - 3abc = 343 - 24

a³ + b³ + c³ - 3abc = 319 [ • Required answer ]

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