a+b+c =7and ab+bc+ca=12then
Find the value of a^3+b^3+c^3-3abc
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a + b + c = 7
ab + bc + ca = 12
Now ,
( a + b + c )³ = a³ + b³ + c³ - 3abc + 2 ( ab + bc + ca )
( 7 )³ = a³ + b³ + c³ - 3abc + 2 × 12
343 = a³ + b³ + c³ - 3abc + 24
a³ + b³ + c³ - 3abc = 343 - 24
a³ + b³ + c³ - 3abc = 319 [ • Required answer ]
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