a+b+c=8
ab+bc+ac=18
then find , a^b^c
i want the actual no. which i have taken plz... plz..
Answers
Answered by
1
Answer:
Step-by-step explanation:
/*By algebraic identity:
a²+b²+c² = (a+b+c)²-2(ab+bc+ca)
= 8²-2×19 [From (1) & (2)]
= 64 - 38
= 26
Therefore,
•••♪
Similar questions