Question

a+b+c=9, a^2+b^2+c^2=35, then find a^3+b^3+c^3=3abc

Answer 1

Answer:

Wrong question

Step-by-step explanation:

Answer 2

Answer:

a+b+c=9

squaring both side

(a+b+c)^2=(9)^2

a^2+b^2+c^2+2ab+2bc+2ac=81

a^2+b^2+c^2+2(ab+bc+ac)=81

35+2(ab+bc+ac)=81

2(ab+bc+ac)=81-35

ab+bc+ac=46\2

ab+bc+ac=23

a^3+b^3+c^3=(a+b+c)(a^2+b^2+c^2-ab-bc-ac)

(a^3+b^3+c^3)=9×35-2(23)

=9×35-46

=9×12

=108

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