a+b+c =9 ab+bc+ac=15 find the value of a²+b²+c²
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Since (a + b + c)2 = a2 + b2 + c2 + 2 (ab + bc + ca)
∴ (9)2 = a2 + b2 + c2 + 2(15)
81 = a2 + b2 + c2 + 30
∴ a2 + b2 + c2 = 81 – 30 = 51
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Answer is 27
a₊b₊c=9
ab₊bc₊ca=15
a=3,b=3,c=3
ab=3₊3=9
bc=3₊3=9
ca=3₊3=9
a²₊b²₊c²=?
a²=3²,b²=3²,c²=3²
3²=9
3²=9₊9₊9
3²₊3²₊3²=9₊9₊9
27=27
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