Question

a+b+c =9 ab+bc+ca= 15 find a²+b²+c²​

Answer 1

Answer:

51

Step-by-step explanation:

Since (a + b + c)2 = a2 + b2 + c2 + 2 (ab + bc + ca)

∴ (9)2 = a2 + b2 + c2 + 2(15)

81 = a2 + b2 + c2 + 30

∴ a2 + b2 + c2 = 81 – 30 = 51

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Answer 2

Answer:

51

Step-by-step explanation:

(a+b+c)^2=a^2+b^2+c^2+2(ab+bc+ca)

by putting the value,

=>(9)^2=a^2+b^2+c^2+2(15)

=>81=a^2+b^2+c^2+30

=>81-30=a^2+b^2+c^2

=>51=a^2+b^2+c^2

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