a+b+c=9,ab+bc+ca=24,a²+b²+c²=?
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(a+b+c)^2 =
![{a}^{2} + {b}^{2} + {c}^{2} + 2(ab + bc + ca) {a}^{2} + {b}^{2} + {c}^{2} + 2(ab + bc + ca)](https://tex.z-dn.net/?f=+%7Ba%7D%5E%7B2%7D+%2B+%7Bb%7D%5E%7B2%7D+%2B+%7Bc%7D%5E%7B2%7D+%2B+2%28ab+%2B+bc+%2B+ca%29)
(9)^2 = a^2+ b^2 +c^2+ 2 (24)
81 = a^2+ b^2 +c^2 + 48
81 - 48 = a^2+ b^2 +c^2
33 = a^2+ b^2 +c^2
please mark it brainliest... if it heps
(9)^2 = a^2+ b^2 +c^2+ 2 (24)
81 = a^2+ b^2 +c^2 + 48
81 - 48 = a^2+ b^2 +c^2
33 = a^2+ b^2 +c^2
please mark it brainliest... if it heps
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