Question

(a+b+c)=9
ab+bc+ca=26
a3+b3=80,b3+c3=90,c3+a3=38
find a2 b2 c2

Answer 1

Answer:

29

Step-by-step explanation:

$(a + b + c)^{2} = 9^{2}$

$a^{2}$ + $b^{2}$ + $c^{2}$ + 2ab + 2bc + 2ca = 81

$a^{2}$ + $b^{2}$ + $c^{2}$ + 2 (ab + bc + ca) = 81

$a^{2}$ + $b^{2}$ + $c^{2}$ + 2 (26) = 81

$a^{2}$ + $b^{2}$ + $c^{2}$ + 52 = 81

$a^{2}$ + $b^{2}$ + $c^{2}$ = 81 - 52

$a^{2}$ + $b^{2}$ + $c^{2}$ = 29