Math, asked by deepika200570, 10 months ago

A+B+C = 90 then Sin2A+Sin2B+Sin2C

Answers

Answered by arkadas16

1

Answer:

2

Step-by-step explanation:

Sin2A +Sin2B+Sin2C

= Sin2(A+B+C)

= 2Sin90* (As, A+B+C= 90*)

= 2* 1 [ Sin90* =1 ]

= 2

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