A+B+C = 90 then Sin2A+Sin2B+Sin2C
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Answered by
1
Answer:
2
Step-by-step explanation:
Sin2A +Sin2B+Sin2C
= Sin2(A+B+C)
= 2Sin90* (As, A+B+C= 90*)
= 2* 1 [ Sin90* =1 ]
= 2
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