Question

a÷(b+c)≠(a÷b)+(a÷c)

1)a=10 b=2 c=-5

2)a=6 b=3 c=-1
​

Answer 1

Answer:

1) a ÷ (b + c) ≠ (a ÷ b) + (a ÷ c)

》10 ÷ (2 + 7) ≠ (10 ÷ 2) + (10 ÷ 5)

》10 ÷ 9 ≠ 5 + 2

》1.111... ≠ 7

2) a ÷ (b + c) ≠ (a ÷ b) + (a ÷ c)

》6 ÷ (3 + 1) ≠ (6 ÷ 3) + (6 ÷ 1)

》6 ÷ 4 ≠ 2 + 6

》1.5 ≠ 8

Answer 2

Given :

• a=10 b=2 c=-5
• a=6 b=3 c=-1

To find :

• a ÷ (b + c) ≠ (a ÷ b) + (a ÷ c)

Solution :

⇒ Let's verify.

→ a ÷ (b + c) ≠ (a ÷ b) + (a ÷ c)

→ 10 ÷ (2 + 5) ≠ (10 ÷ 2) + (10 ÷ 5)

→ 10 ÷ (7) ≠ (5) + (10 ÷ 5)

→ 10 ÷ (7) ≠ (5) + (2)

→ 1.42 ≠ 7

• Therefore,  a ÷ (b + c) ≠ (a ÷ b) + (a ÷ c).

→ a ÷ (b + c) ≠ (a ÷ b) + (a ÷ c)

→ 6 ÷ {3 + (-1)} ≠ (6 ÷ 3) + (6 ÷ -1)

→ 6 ÷ (2) ≠ (2) + (-6)

→ 3 ≠ -4

• Therefore,  a ÷ (b + c) ≠ (a ÷ b) + (a ÷ c).