{(a+b+c)(-a+b+c)(a-b+c)(a+b-c)}/4a^2b^2 is
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Therefore AE = 2AD => AB+ AC = 2 AD 3) If O, A, B, C are four points such ... AB = AO + OB = - 10a + 5b = 5(b - 2a) BC = BO + OC =-5b + 4a + 3b = 4a -2b = -2(b-2a) i.e. BC ...
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