(a+b+c) (a-b+c) = a² + b² + c²
a(a-b-c) + b( ? ) + c( ? ) = a²+b²+c²
( ? ) + 2ac = b²
2ac = ( ? )
b² = ( ? )
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Answer:
your ans is b^ = a^2
Step-by-step explanation:
(a+b+c) (a-b+c) = a² + b² + c²
a(a-b-c) + b( a + b + c) + c( a +b + c) = a²+b²+c²
( a^2 ) + 2ac = b²
2ac = ( a^2 + b^2)
b² = ( a^2 )
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