(a + b + c) (a - b + c) = (a² + b² + c² ) where a = ck² b= ck
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Answered by
7
Answer:
To Prove : (a+b+c)(a−b+c)=a²+b²+c²
Proof : a,b,c are in continued proportion.
∴ ba=cb=k (let)
b=ck
a=bk=(ck)k =ck²
L.H.S. =(ck²+ck+c)(ck²−ck+c)
=c²(k²+k+1)(k²−k+1)
=c²[(k²+1)2−(k)²]
=c²[k4+²k²+1−k²]
=c²[k4+k²+1]
R.H.S. =c²k4+c
hope it helps you
Answered by
2
Answer:
ooh ok xD
btw how r u
wht about ur cousin
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