a-[b-{c-(a-b-c)}-c]+a=.... saralrup dya
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Answered by
1
Answer:
Case 1. If a,b,c are lengths of triangle.
Since
2xy−−√≤x+y2yz−−√≤y+z2zx−−√≤z+x
for x,y,z≥0, then multiplying this inequalities we get
8xyz≤(x+y)(y+z)(z+x)
Now substitute
x=a+b−c2y=a−b+c2z=−a+b+c2
Answered by
1
Answer:
a+b+c and this is my opinion
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