Math, asked by iamaboy47, 5 months ago

(a-b/c+a-c/b)^2-(d-b/c+d-c/b)^2=(a-d)^2(1/c^2-1/b^2)

Answers

Answered by Jashanmundian

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(a-b/c+a-c/b)^2-(d-b/c+d-c/b)^2=(a-d)^2(1/c^2-1/b^2)​

Answers

(a-b/c+a-c/b)^2-(d-b/c+d-c/b)^2=(a-d)^2(1/c^2-1/b^2)