Question

(a-b/c +a-c/b)²-(d-b/c+d-c/b)²= (a-d)²*(1/c²-1/b²
)​

Answer 1

Answer:

a,b,c,d are in continued proportion

D === K

d

-a-dk³, b=dk², c-dk

= (a = b + a = c)²-(d=b+d=²)

LHS =

dk² dk.)³² - ( d =

dk-dk² dk³-dk

dk

+

d-dk²

dk

(K³-1)² (^²-1)²

RHS = (a - d)² - 1

1