(A-B)-C=(A-C)∩(B-C)
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Answer:
(A-B)-C=(A-C)Π(B-C)
(X,Y)€(A-B)-C
X€A and X€B and Y€C
(X,Y)€(A and C) and (B and C)
(X,Y)€(A-C)Π(B-C)
(A-B)-C€(A-C)Π(B-C)........(i)
(A-C)Π(B-C)€(A-B)-C.........(ii)
From (i) and (ii) we get
(A-B)-C=(A-C)Π(B-C)
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