(a+b+c)(a2+b2+c2)-ab(a+b+c)-bc(a+b+c)-ca(a+b+c)
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Answered by
0
Answer:
(a+b+c)(a²+b²+c²-ab-bc-ca)
(a+b+c)[(a-b)²+(b-c)²+(c-a)²]
a²+b²+c²-3abc
Answered by
1
Answer:
a³+b³+c³-3abc
Step-by-step explanation:
= (a+b+c)(a²+b²+c²)-(ab+bc+ca)(a+b+c)
= (a+b+c){a²+b²+c²-(ab+bc+ca)}
= (a+b+c){a²+b²+c²-ab-bc-ca}
= a³+b³+c³-3abc
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