Question

(a+b+c)(a2+b2+c2)-ab(a+b+c)-bc(a+b+c)-ca(a+b+c)​

Answer 1

Answer:

(a+b+c)(a²+b²+c²-ab-bc-ca)

(a+b+c)[(a-b)²+(b-c)²+(c-a)²]

a²+b²+c²-3abc

Answer 2

Answer:

a³+b³+c³-3abc

Step-by-step explanation:

= (a+b+c)(a²+b²+c²)-(ab+bc+ca)(a+b+c)

= (a+b+c){a²+b²+c²-(ab+bc+ca)}

= (a+b+c){a²+b²+c²-ab-bc-ca}

= a³+b³+c³-3abc