Math, asked by sanjana09july, 11 months ago

(a_b_c) ÷-a3 +b3 +c3 +3abc

Answers

Answered by uday4344

0

What value do you want

Answered by cashedjohnny123

1

Answer:

(a+b+c)/a³+b³+c³-3abc

=(a+b+c)/(a+b+c)(a²+b²+c²-ab-bc-ca)

= 1/a²+b²+c²-ab-bc-ca

hope this help

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